Monday, 2 April 2012

More Math

Good afternoon blog readers. It is a very beautiful afternoon in southern Alberta with our warm weather coming back.
 Yesterday we had Janice and Nacho over and since they started the blog that I linked you to, we were talking about blogs. Joshua let me know that he would like some more math challenges so here you go. I'll give you one example and then one problem.
 EXAMPLE: Find three consecutive odd integers such that 4 times the first is 14 less than twice the sum of 2 and the third.
             N, N+2, N+4,                            So the Integers are -1, 1, 3
             4(N) + 14 = 2(2 + N+4)         4(-1) +14 = 2(2 +3)
             4N + 14 = 4 + 2N +8             -4 +14 = 4+6
             4N +14 = 12 +2N                    10 = 10
         _____-12__-12__________          
             4N +2 =2N
        __-4N       -4N             
                  2 = -2N
Okay, now here is the problem:  Find four consecutive even integers such that -6 times the sum of the second and fourth is 8 less than 11 times the opposite of the third. Please comment for your answer. I hope that I made sense to you.
                   Yesenia

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